RuntimeError: Working Outside of Application Context
Armin Ronacher
—The ProblemJump To Solution
Traceback (most recent call last): File "app.py", line 30, in init_db db = get_db() File "app.py", line 41, in get_db g.sqlite_db = connect_db() File "/usr/local/lib/python2.7/site-packages/werkzeug/local.py", line 355, in <lambda> __setattr__ = lambda x, n, v: setattr(x._get_current_object(), n, v) File "/usr/local/lib/python2.7/site-packages/werkzeug/local.py", line 297, in _get_current_object return self.__local() File "/usr/local/lib/python2.7/site-packages/flask/globals.py", line 27, in _lookup_app_object raise RuntimeError('working outside of application context') RuntimeError: working outside of application context
The Solution
Flask requires application context be available when accessing certain items, such as the g construct. Many of these accessors are simply a proxy for the current version, which is bound to the Flask application context.
For example, if you’ve got a command line app, you simply need to instantiate your app and push a context:
from flask import Flask, current_app app = Flask(__name__) with app.app_context(): # within this block, current_app points to app. print current_app.name
Further Reading
If you’re looking to get a deeper understanding of how Flask application monitoring works, take a look at the following articles:
- SentryFlask Error Monitoring
- Community SeriesIdentify, Trace, and Fix Endpoint Regression Issues
- Listen to the Syntax Podcast
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